### Problem Statement

You are given two identical node structures, `rootA` and `rootB`, along with a specific node, `nodeA`, within `rootA`. Your task is to determine the path from `nodeA` to `rootA`, and then use this path to find the value of the node at the identical position within `rootB`.

### Example

Consider the following structures:

```html
<div id="rootA">
    <div>
        <div>
            <div></div>
            <div>
                <div></div>
                <div>
                    <div id="nodeA">Node A Value</div>
                </div>
            </div>
        </div>
    </div>
    <div></div>
</div>
<div id="rootB">
    <div>
        <div>
            <div></div>
            <div>
                <div></div>
                <div>
                    <div>Node B Value</div>
                </div>
            </div>
        </div>
    </div>
    <div></div>
</div>
```

**Input**:
- `rootA`: The root node of the first identical structure.
- `rootB`: The root node of the second identical structure.
- `nodeA`: A specific node within `rootA`.

**Output**:
- The value of the node at the identical position within `rootB`.

### Explanation

Given `rootA` and `rootB`, and a specific `nodeA` in `rootA`:
1. Determine the path from `nodeA` to `rootA`.
2. Use this path to traverse from `rootB` to the corresponding node.
3. Return the value of the corresponding node in `rootB`.

**Expected Output**:
- For the given example, the output would be "Node B Value".

index.html

index.js

DOM Finder

### Editorial

The given task is to find the value of a node in a structure `rootB` that corresponds to the position of a specific node `nodeA` in an identical structure `rootA`. The solution involves two main steps: determining the path from `nodeA` to `rootA` and using this path to find the corresponding node in `rootB`.

#### Step-by-Step Solution

1. **Finding the Path from `nodeA` to `rootA`**:
   - **Function**: `getPathFromChildToParent(parent, child)`
   - **Logic**:
     - Start from `nodeA` and traverse up to `rootA`.
     - For each node, find its index within its parent's children.
     - Push these indices into an array to form the path.
     - Continue this process until reaching `rootA`.
   - **Code**:
     ```javascript
     const getPathFromChildToParent = (parent, child) => {
         let currentNode = child;
         const pathArray = [];
         while (currentNode !== parent) {
             const parentElement = currentNode.parentElement;
             const childrenArray = Array.from(parentElement.children);
             pathArray.push(childrenArray.indexOf(currentNode));
             currentNode = parentElement;
         }
         return pathArray;
     };
     ```

2. **Finding the Value in `rootB` Using the Path**:
   - **Function**: `getValueFromPath(parent, path)`
   - **Logic**:
     - Start from `rootB`.
     - Use the path array to traverse down the DOM tree.
     - For each index in the path array, navigate to the corresponding child node.
     - Return the value of the final node.
   - **Code**:
     ```javascript
     const getValueFromPath = (parent, path) => {
         let currentNode = parent;
         while (path.length) {
             currentNode = currentNode.children[path.pop()];
         }
         return currentNode.innerText;
     };
     ```

3. **Orchestrating the Process**:
   - **Function**: `findNodeValue()`
   - **Logic**:
     - Get the root elements and the specific node `nodeA`.
     - Determine the path from `nodeA` to `rootA`.
     - Use this path to find the corresponding value in `rootB`.
   - **Code**:
     ```javascript
     const findNodeValue = () => {
         const rootA = document.getElementById('rootA');
         const rootB = document.getElementById('rootB');
         const nodeA = document.getElementById('nodeA');
         const path = getPathFromChildToParent(rootA, nodeA);
         return getValueFromPath(rootB, path);
     };

     document.getElementById('output').innerHTML = findNodeValue()
     ```

### Explanation of the JavaScript Code

1. **getPathFromChildToParent**:
   - This function computes the path from a child node to a parent node.
   - It iterates from the child node upwards, recording the index of each node within its parent's children.
   - The path is stored in an array and returned.

2. **getValueFromPath**:
   - This function navigates through a parent node's children using a given path.
   - It starts from the parent node and follows the indices in the path array to reach the target node.
   - The inner text of the target node is returned.

3. **findNodeValue**:
   - This function combines the previous two functions to find the value of the corresponding node in an identical DOM structure.
   - It first calculates the path from `nodeA` to `rootA`, then uses this path to find and return the value of the corresponding node in `rootB`.

### Complete Code Implementation

**HTML:**
```html
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Find Node Value</title>
</head>
<body>
    <div id="rootA">
        <div>
            <div>
                <div></div>
                <div>
                    <div></div>
                    <div>
                        <div id="nodeA">Node A Value</div>
                    </div>
                </div>
            </div>
        </div>
        <div></div>
    </div>
    <div id="rootB">
        <div>
            <div>
                <div></div>
                <div>
                    <div></div>
                    <div>
                        <div>Node B Value</div>
                    </div>
                </div>
            </div>
        </div>
        <div></div>
    </div>
    <script src="./index.js"></script>
</body>
</html>
```

**JavaScript (`script.js`):**
```javascript
const getPathFromChildToParent = (parent, child) => {
    let currentNode = child;
    const pathArray = [];
    while (currentNode !== parent) {
        const parentElement = currentNode.parentElement;
        const childrenArray = Array.from(parentElement.children);
        pathArray.push(childrenArray.indexOf(currentNode));
        currentNode = parentElement;
    }
    return pathArray;
};

const getValueFromPath = (parent, path) => {
    let currentNode = parent;
    while (path.length) {
        currentNode = currentNode.children[path.pop()];
    }
    return currentNode.innerText;
};

const findNodeValue = () => {
    const rootA = document.getElementById('rootA');
    const rootB = document.getElementById('rootB');
    const nodeA = document.getElementById('nodeA');
    const path = getPathFromChildToParent(rootA, nodeA);
    return getValueFromPath(rootB, path);
};

document.getElementById('output').innerHTML = findNodeValue()
```

This code effectively demonstrates how to navigate identical DOM structures and find corresponding nodes based on a calculated path.